How it works
Heat transfer rate = conductivity × area × temperature difference / thickness for one-dimensional steady conduction.
Input definitions
- Thermal conductivity (W/m·K)
- Enter the value in the labeled unit.
- Area (m²)
- Enter the value in the labeled unit.
- Temperature difference (K)
- Enter the value in the labeled unit.
- Thickness (m)
- Enter the value in the labeled unit.
A worked example
- Thermal conductivity (W/m·K)
- 0.04
- Area (m²)
- 10
- Temperature difference (K)
- 20
- Thickness (m)
- 0.1
Assumptions & limits
Ideal educational model in the stated SI units. Real equipment, structural design and safety decisions need appropriate professional analysis; losses are excluded unless entered.
Sources & review
Maintained by AnsRio. Methods and examples use automated checks; this does not imply independent professional certification.
Method updated 2026-10-18. Content checked against the stated method and examples. Our verification approach.
Common questions
Does this include surface air films and thermal bridges?
No. It models a homogeneous slab with constant conductivity. Building U-values require surface resistances, layer stacks and bridge analysis.
How does Steady thermal conduction through a slab work?
Heat transfer rate = conductivity × area × temperature difference / thickness for one-dimensional steady conduction.
What should I check before using Steady thermal conduction through a slab?
Ideal educational model in the stated SI units. Real equipment, structural design and safety decisions need appropriate professional analysis; losses are excluded unless entered.