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Electronics & energy

Three-phase AC voltage drop

Three-phase AC voltage drop: Drop = √3 × current × length/1,000 × (R × PF + X × √(1−PF²)).

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How it works

Drop = √3 × current × length/1,000 × (R × PF + X × √(1−PF²)).

Input definitions

Line current (A)
Enter the value in the labeled unit.
One-way length (m)
Enter the value in the labeled unit.
Resistance (Ω/km)
Enter the value in the labeled unit.
Reactance (Ω/km)
Enter the value in the labeled unit.
Power factor
Enter the value in the labeled unit.

A worked example

Line current (A)
60
One-way length (m)
100
Resistance (Ω/km)
0.5
Reactance (Ω/km)
0.08
Power factor
0.85
4.854688

Assumptions & limits

Uses only the values entered. Rates are illustrative inputs, not live quotes, legal rules or personalised advice. Check provider terms, local requirements and measurements before acting.

Sources & review

Maintained by AnsRio. Methods and examples use automated checks; this does not imply independent professional certification.

Method updated 2026-10-19. Content checked against the stated method and examples. Our verification approach.

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Common questions

Why include reactance?

Long AC feeders and larger conductors can have material reactance, especially at lower power factor.

How does Three-phase AC voltage drop calculate the result?

Drop = √3 × current × length/1,000 × (R × PF + X × √(1−PF²)).

What should I verify before using Three-phase AC voltage drop?

Uses only the values entered. Rates are illustrative inputs, not live quotes, legal rules or personalised advice. Check provider terms, local requirements and measurements before acting.

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